12/31/2014 · Solution. Let the work by (x-1) men in (x+1) days = 9z. Then, work done by 1 man in 1 days = [9z/ (x-1) * 1/ (x+1)] Let the work done by (x+2) men in (x-1) days = 10z. Therefore Work done by 1 man in 1 days = 10z/ (x+2) (x-1) Therefore. 9z/ (x-1) (x+1) = 10z/ (x+2) (x-1) Solve. x=8.
If the work done by (x – 1 ) men in (x + 1 ) days and the work done by (x + 2) men in (x – 1 ) days are in the ratio 9 : 10, then the value of x is equal to ? a) 5 b) 6 c) 7 d) 8, Click here ?? to get an answer to your question ? If the work done by (x-1 ) men in (x+1) days is to the work done by(x+2) men in (x- 1 ) days in the ratio of 9:1…, If the work done by (x –1) men in (x + 1) days is to the work done by (x + 2) men in (x – 1) days are in the ratio 9 : 10, then the value of x is equal, Find an answer to your question If the ratio of work done by (x-1 ) men in (x+1)days to the work done by (x+2)men in (x- 1 )days is 9:10, then x is equal to, If the work done by ( Large left(x- 1 right) ) men in ( Large left(x+1right) )days and the work done by( Large left(x+2right) ) men in ( Large left(x- 1 right) ).
Question 1169666: Part of a work done in (x + 1 ) hours if the work can be done (2x-5) hours. Answer by ikleyn(35340) ( Show Source ): You can put this solution on YOUR website!
